The uniform rod of mass 20 kg and length of 1.6 m is pivoted at its end and swings freely in the vertical plane. Angular acceleration of rod just after the rod is released from rest in the horizontal position.
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Text Solution
Verified by ExpertsThe correct answer is:
A
Initial velocity of each point onthe rod is zero so angular velocity of rod is zero.
Torque about O
T = Ι α
20g (0.8) = 
⇒ 20g (0.8) = 
⇒ 
= α = angular acceleration
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